Base | Representation |
---|---|
bin | 10010111010011111… |
… | …01000011100000001 |
3 | 222012200010120102012 |
4 | 21131033220130001 |
5 | 131244001012343 |
6 | 4355334102305 |
7 | 506430145313 |
oct | 113517503401 |
9 | 28180116365 |
10 | 10154313473 |
11 | 4340933007 |
12 | 1b747aa995 |
13 | c5a969815 |
14 | 6c48517b3 |
15 | 3e66e0718 |
hex | 25d3e8701 |
10154313473 has 2 divisors, whose sum is σ = 10154313474. Its totient is φ = 10154313472.
The previous prime is 10154313461. The next prime is 10154313487. The reversal of 10154313473 is 37431345101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6167275024 + 3987038449 = 78532^2 + 63143^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10154313473 is a prime.
It is a super-2 number, since 2×101543134732 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10154312473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5077156736 + 5077156737.
It is an arithmetic number, because the mean of its divisors is an integer number (5077156737).
Almost surely, 210154313473 is an apocalyptic number.
It is an amenable number.
10154313473 is a deficient number, since it is larger than the sum of its proper divisors (1).
10154313473 is an equidigital number, since it uses as much as digits as its factorization.
10154313473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 10154313473 its reverse (37431345101), we get a palindrome (47585658574).
The spelling of 10154313473 in words is "ten billion, one hundred fifty-four million, three hundred thirteen thousand, four hundred seventy-three".
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