1015552541537 has 2 divisors, whose sum is σ = 1015552541538. Its totient is φ = 1015552541536.

The previous prime is 1015552541513. The next prime is 1015552541557. The reversal of 1015552541537 is 7351452555101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 795005840161 + 220546701376 = 891631^2 + 469624^2 .

It is a cyclic number.

It is not a de Polignac number, because 1015552541537 - 2¹⁴ = 1015552525153 is a prime.

It is a super-2 number, since 2×1015552541537² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1015552541557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507776270768 + 507776270769.

It is an arithmetic number, because the mean of its divisors is an integer number (507776270769).

Almost surely, 2^{1015552541537} is an apocalyptic number.

It is an amenable number.

1015552541537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1015552541537 is an equidigital number, since it uses as much as digits as its factorization.

1015552541537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 525000, while the sum is 44.

The spelling of 1015552541537 in words is "one trillion, fifteen billion, five hundred fifty-two million, five hundred forty-one thousand, five hundred thirty-seven".