Search a number
-
+
10159723465321 is a prime number
BaseRepresentation
bin1001001111010111111010…
…1101010100101001101001
31022222021000121002222120011
42103311332231110221221
52312424103201342241
633335151301131521
72066005263402043
oct223657655245151
938867017088504
1010159723465321
11326779503a621
1211810329b9ba1
1358909a021b51
14271a3a01aa93
151294274a9281
hex93d7eb54a69

10159723465321 has 2 divisors, whose sum is σ = 10159723465322. Its totient is φ = 10159723465320.

The previous prime is 10159723465249. The next prime is 10159723465379. The reversal of 10159723465321 is 12356432795101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9974448315225 + 185275150096 = 3158235^2 + 430436^2 .

It is a cyclic number.

It is not a de Polignac number, because 10159723465321 - 215 = 10159723432553 is a prime.

It is not a weakly prime, because it can be changed into another prime (10159723465121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5079861732660 + 5079861732661.

It is an arithmetic number, because the mean of its divisors is an integer number (5079861732661).

Almost surely, 210159723465321 is an apocalyptic number.

It is an amenable number.

10159723465321 is a deficient number, since it is larger than the sum of its proper divisors (1).

10159723465321 is an equidigital number, since it uses as much as digits as its factorization.

10159723465321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 10159723465321 in words is "ten trillion, one hundred fifty-nine billion, seven hundred twenty-three million, four hundred sixty-five thousand, three hundred twenty-one".