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10166056155993 = 33388685385331
BaseRepresentation
bin1001001111101111100000…
…1010100111101101011001
31022222212100221012000001010
42103323320022213231121
52313030040333442433
633342115520444133
72066321230363053
oct223737012475531
938885327160033
1010166056155993
11326a444742881
1211822bb779649
13589868cc32aa
1427207b0ac8d3
1512969840be63
hex93ef82a7b59

10166056155993 has 4 divisors (see below), whose sum is σ = 13554741541328. Its totient is φ = 6777370770660.

The previous prime is 10166056155973. The next prime is 10166056156033. The reversal of 10166056155993 is 39955165066101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10166056155993 - 212 = 10166056151897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10166056155973) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1694342692663 + ... + 1694342692668.

It is an arithmetic number, because the mean of its divisors is an integer number (3388685385332).

Almost surely, 210166056155993 is an apocalyptic number.

It is an amenable number.

10166056155993 is a deficient number, since it is larger than the sum of its proper divisors (3388685385335).

10166056155993 is an equidigital number, since it uses as much as digits as its factorization.

10166056155993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3388685385334.

The product of its (nonzero) digits is 6561000, while the sum is 57.

The spelling of 10166056155993 in words is "ten trillion, one hundred sixty-six billion, fifty-six million, one hundred fifty-five thousand, nine hundred ninety-three".

Divisors: 1 3 3388685385331 10166056155993