101899599284736 has 1120 divisors, whose sum is σ = 340511431677120. Its totient is φ = 30189492633600.

The previous prime is 101899599284731. The next prime is 101899599284753. The reversal of 101899599284736 is 637482995998101.

101899599284736 is a `hidden beast` number, since 1 + 0 + 1 + 8 + 9 + 9 + 59 + 92 + 8 + 473 + 6 = 666.

It is a Harshad number since it is a multiple of its sum of digits (81).

It is not an unprimeable number, because it can be changed into a prime (101899599284731) by changing a digit.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 44830442896 + ... + 44830445168.

It is a 2-persistent number, because it is pandigital, and so is 2⋅101899599284736 = 203799198569472, but 3⋅101899599284736 = 305698797854208 is not.

Almost surely, 2^{101899599284736} is an apocalyptic number.

101899599284736 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101899599284736, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170255715838560).

101899599284736 is an abundant number, since it is smaller than the sum of its proper divisors (238611832392384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101899599284736 is an equidigital number, since it uses as much as digits as its factorization.

101899599284736 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2560 (or 2529 counting only the distinct ones).

The product of its (nonzero) digits is 2116316160, while the sum is 81.

The spelling of 101899599284736 in words is "one hundred one trillion, eight hundred ninety-nine billion, five hundred ninety-nine million, two hundred eighty-four thousand, seven hundred thirty-six".