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10201322312131 is a prime number
BaseRepresentation
bin1001010001110010111000…
…1100010101000111000011
31100010020101200200100120011
42110130232030111013003
52314114302002442011
633410231152525351
72102010163640566
oct224345614250703
940106350610504
1010201322312131
1132833a1551965
121189102250857
1358cc993c52c2
14273a64a9c4dd
1512a55e513621
hex9472e3151c3

10201322312131 has 2 divisors, whose sum is σ = 10201322312132. Its totient is φ = 10201322312130.

The previous prime is 10201322312119. The next prime is 10201322312149. The reversal of 10201322312131 is 13121322310201.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10201322312131 - 211 = 10201322310083 is a prime.

It is a super-2 number, since 2×102013223121312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10201322310131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5100661156065 + 5100661156066.

It is an arithmetic number, because the mean of its divisors is an integer number (5100661156066).

Almost surely, 210201322312131 is an apocalyptic number.

10201322312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10201322312131 is an equidigital number, since it uses as much as digits as its factorization.

10201322312131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10201322312131 its reverse (13121322310201), we get a palindrome (23322644622332).

The spelling of 10201322312131 in words is "ten trillion, two hundred one billion, three hundred twenty-two million, three hundred twelve thousand, one hundred thirty-one".