Base | Representation |
---|---|
bin | 1001010001110101100010… |
… | …0000010101111011000011 |
3 | 1100010022020011110110120201 |
4 | 2110131120200111323003 |
5 | 2314122230220421121 |
6 | 33410425432150031 |
7 | 2102033603620621 |
oct | 224353040257303 |
9 | 40108204413521 |
10 | 10202032201411 |
11 | 3283726236216 |
12 | 118927bb38317 |
13 | 5900804b7a2b |
14 | 273ad108c511 |
15 | 12a5a19dae91 |
hex | 94758815ec3 |
10202032201411 has 2 divisors, whose sum is σ = 10202032201412. Its totient is φ = 10202032201410.
The previous prime is 10202032201393. The next prime is 10202032201423. The reversal of 10202032201411 is 11410223020201.
It is a strong prime.
It is an emirp because it is prime and its reverse (11410223020201) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10202032201411 is a prime.
It is a super-3 number, since 3×102020322014113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (10202032211411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101016100705 + 5101016100706.
It is an arithmetic number, because the mean of its divisors is an integer number (5101016100706).
Almost surely, 210202032201411 is an apocalyptic number.
10202032201411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10202032201411 is an equidigital number, since it uses as much as digits as its factorization.
10202032201411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10202032201411 its reverse (11410223020201), we get a palindrome (21612255221612).
The spelling of 10202032201411 in words is "ten trillion, two hundred two billion, thirty-two million, two hundred one thousand, four hundred eleven".
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