Base | Representation |
---|---|
bin | 11101101100011101100… |
… | …11100100011100010001 |
3 | 10121112120200100102020221 |
4 | 32312032303210130101 |
5 | 113204040100214213 |
6 | 2100415405033041 |
7 | 133500030346654 |
oct | 16661663443421 |
9 | 3545520312227 |
10 | 1020303132433 |
11 | 363787578892 |
12 | 1458a9555781 |
13 | 752a26c9c80 |
14 | 37550ab989b |
15 | 1b818e0e38d |
hex | ed8ece4711 |
1020303132433 has 32 divisors (see below), whose sum is σ = 1109779646976. Its totient is φ = 932457681408.
The previous prime is 1020303132421. The next prime is 1020303132449. The reversal of 1020303132433 is 3342313030201.
It is a cyclic number.
It is not a de Polignac number, because 1020303132433 - 29 = 1020303131921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1020303132398 and 1020303132407.
It is not an unprimeable number, because it can be changed into a prime (1020303132533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 634910916 + ... + 634912522.
It is an arithmetic number, because the mean of its divisors is an integer number (34680613968).
Almost surely, 21020303132433 is an apocalyptic number.
1020303132433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1020303132433 is a deficient number, since it is larger than the sum of its proper divisors (89476514543).
1020303132433 is a wasteful number, since it uses less digits than its factorization.
1020303132433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2913.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 1020303132433 its reverse (3342313030201), we get a palindrome (4362616162634).
The spelling of 1020303132433 in words is "one trillion, twenty billion, three hundred three million, one hundred thirty-two thousand, four hundred thirty-three".
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