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1020304314313 = 4980720485159
BaseRepresentation
bin11101101100011101110…
…00000100111111001001
310121112120202120110111021
432312032320010333021
5113204040401024223
62100415450232441
7133500043401454
oct16661670047711
93545522513437
101020304314313
11363788205849
121458a9a25721
13752a2a21bcb
1437550d0649b
151b81909465d
hexed8ee04fc9

1020304314313 has 4 divisors (see below), whose sum is σ = 1020324849280. Its totient is φ = 1020283779348.

The previous prime is 1020304314283. The next prime is 1020304314361. The reversal of 1020304314313 is 3134134030201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1020304314313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1020304314713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10192773 + ... + 10292386.

It is an arithmetic number, because the mean of its divisors is an integer number (255081212320).

Almost surely, 21020304314313 is an apocalyptic number.

It is an amenable number.

1020304314313 is a deficient number, since it is larger than the sum of its proper divisors (20534967).

1020304314313 is an equidigital number, since it uses as much as digits as its factorization.

1020304314313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20534966.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1020304314313 its reverse (3134134030201), we get a palindrome (4154438344514).

The spelling of 1020304314313 in words is "one trillion, twenty billion, three hundred four million, three hundred fourteen thousand, three hundred thirteen".

Divisors: 1 49807 20485159 1020304314313