Search a number
-
+
102042140113 is a prime number
BaseRepresentation
bin101111100001000101…
…1110111110111010001
3100202101111021210211201
41133002023313313101
53132440241440423
6114513313111201
710241461610524
oct1370213676721
9322344253751
10102042140113
113a304145201
1217939858501
13981291c784
144d20368bbb
1529c36732ad
hex17c22f7dd1

102042140113 has 2 divisors, whose sum is σ = 102042140114. Its totient is φ = 102042140112.

The previous prime is 102042140099. The next prime is 102042140117. The reversal of 102042140113 is 311041240201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62977408209 + 39064731904 = 250953^2 + 197648^2 .

It is a cyclic number.

It is not a de Polignac number, because 102042140113 - 213 = 102042131921 is a prime.

It is a super-2 number, since 2×1020421401132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102042140117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51021070056 + 51021070057.

It is an arithmetic number, because the mean of its divisors is an integer number (51021070057).

Almost surely, 2102042140113 is an apocalyptic number.

It is an amenable number.

102042140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102042140113 is an equidigital number, since it uses as much as digits as its factorization.

102042140113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 102042140113 its reverse (311041240201), we get a palindrome (413083380314).

The spelling of 102042140113 in words is "one hundred two billion, forty-two million, one hundred forty thousand, one hundred thirteen".