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102101113 is a prime number
BaseRepresentation
bin1100001010111…
…11000001111001
321010010021101201
412011133001321
5202114213423
614044214201
72346562612
oct605370171
9233107351
10102101113
11526a7094
122a23a361
13181cac7a
14d7bac09
158e6c2ad
hex615f079

102101113 has 2 divisors, whose sum is σ = 102101114. Its totient is φ = 102101112.

The previous prime is 102101107. The next prime is 102101143. The reversal of 102101113 is 311101201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98247744 + 3853369 = 9912^2 + 1963^2 .

It is an emirp because it is prime and its reverse (311101201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102101113 - 29 = 102100601 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102101113.

It is not a weakly prime, because it can be changed into another prime (102101143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050556 + 51050557.

It is an arithmetic number, because the mean of its divisors is an integer number (51050557).

Almost surely, 2102101113 is an apocalyptic number.

It is an amenable number.

102101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102101113 is an equidigital number, since it uses as much as digits as its factorization.

102101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 102101113 is about 10104.5095378252. The cubic root of 102101113 is about 467.3872117742.

Adding to 102101113 its reverse (311101201), we get a palindrome (413202314).

The spelling of 102101113 in words is "one hundred two million, one hundred one thousand, one hundred thirteen".