10210212113 has 4 divisors (see below), whose sum is σ = 10217368560. Its totient is φ = 10203055668.

The previous prime is 10210212041. The next prime is 10210212127. The reversal of 10210212113 is 31121201201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121201201 = 29 ⋅1073144869.

It is a cyclic number.

It is not a de Polignac number, because 10210212113 - 2¹² = 10210208017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10210212163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3576083 + ... + 3578936.

It is an arithmetic number, because the mean of its divisors is an integer number (2554342140).

Almost surely, 2^10210212113 is an apocalyptic number.

It is an amenable number.

10210212113 is a deficient number, since it is larger than the sum of its proper divisors (7156447).

10210212113 is an equidigital number, since it uses as much as digits as its factorization.

10210212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7156446.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10210212113 its reverse (31121201201), we get a palindrome (41331413314).

The spelling of 10210212113 in words is "ten billion, two hundred ten million, two hundred twelve thousand, one hundred thirteen".