Base | Representation |
---|---|
bin | 11101101101110100011… |
… | …01011011000101000001 |
3 | 10121121110102120200200101 |
4 | 32312322031123011001 |
5 | 113212033010030423 |
6 | 2101015540522401 |
7 | 133524052052164 |
oct | 16667215330501 |
9 | 3547412520611 |
10 | 1021031330113 |
11 | 364020627553 |
12 | 145a713b0401 |
13 | 7538a52cb82 |
14 | 375bd6b3adb |
15 | 1b85cd017ad |
hex | edba35b141 |
1021031330113 has 2 divisors, whose sum is σ = 1021031330114. Its totient is φ = 1021031330112.
The previous prime is 1021031330069. The next prime is 1021031330161. The reversal of 1021031330113 is 3110331301201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 572068347904 + 448962982209 = 756352^2 + 670047^2 .
It is an emirp because it is prime and its reverse (3110331301201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1021031330113 - 233 = 1012441395521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1021031330173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510515665056 + 510515665057.
It is an arithmetic number, because the mean of its divisors is an integer number (510515665057).
Almost surely, 21021031330113 is an apocalyptic number.
It is an amenable number.
1021031330113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021031330113 is an equidigital number, since it uses as much as digits as its factorization.
1021031330113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1021031330113 its reverse (3110331301201), we get a palindrome (4131362631314).
The spelling of 1021031330113 in words is "one trillion, twenty-one billion, thirty-one million, three hundred thirty thousand, one hundred thirteen".
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