Base | Representation |
---|---|
bin | 1001010010010111010100… |
… | …0111010111111101011011 |
3 | 1100011011122021010120121012 |
4 | 2110211311013113331123 |
5 | 2314244314121130021 |
6 | 33414525432204135 |
7 | 2102504426010266 |
oct | 224456507277533 |
9 | 40134567116535 |
10 | 10211102130011 |
11 | 328755aa49882 |
12 | 118ab9153964b |
13 | 590b975b01a3 |
14 | 2743118a7cdd |
15 | 12a932dcc35b |
hex | 949751d7f5b |
10211102130011 has 2 divisors, whose sum is σ = 10211102130012. Its totient is φ = 10211102130010.
The previous prime is 10211102129999. The next prime is 10211102130037. The reversal of 10211102130011 is 11003120111201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10211102130011 is a prime.
It is a super-2 number, since 2×102111021300112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10211102130811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105551065005 + 5105551065006.
It is an arithmetic number, because the mean of its divisors is an integer number (5105551065006).
Almost surely, 210211102130011 is an apocalyptic number.
10211102130011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10211102130011 is an equidigital number, since it uses as much as digits as its factorization.
10211102130011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 10211102130011 its reverse (11003120111201), we get a palindrome (21214222241212).
The spelling of 10211102130011 in words is "ten trillion, two hundred eleven billion, one hundred two million, one hundred thirty thousand, eleven".
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