Base | Representation |
---|---|
bin | 101111100011001001… |
… | …0111111100001000011 |
3 | 100202120022002010001102 |
4 | 1133012102333201003 |
5 | 3133110421142311 |
6 | 114524215325015 |
7 | 10243260105461 |
oct | 1370622774103 |
9 | 322508063042 |
10 | 102111115331 |
11 | 3a33a076315 |
12 | 1795898076b |
13 | 9823cbca04 |
14 | 4d295a1831 |
15 | 29c974a43b |
hex | 17c64bf843 |
102111115331 has 2 divisors, whose sum is σ = 102111115332. Its totient is φ = 102111115330.
The previous prime is 102111115297. The next prime is 102111115339. The reversal of 102111115331 is 133511111201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102111115331 - 210 = 102111114307 is a prime.
It is a super-2 number, since 2×1021111153312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (102111115339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055557665 + 51055557666.
It is an arithmetic number, because the mean of its divisors is an integer number (51055557666).
Almost surely, 2102111115331 is an apocalyptic number.
102111115331 is a deficient number, since it is larger than the sum of its proper divisors (1).
102111115331 is an equidigital number, since it uses as much as digits as its factorization.
102111115331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 102111115331 its reverse (133511111201), we get a palindrome (235622226532).
The spelling of 102111115331 in words is "one hundred two billion, one hundred eleven million, one hundred fifteen thousand, three hundred thirty-one".
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