Base | Representation |
---|---|
bin | 101111100011001011… |
… | …0110000011011100001 |
3 | 100202120100221020122220 |
4 | 1133012112300123201 |
5 | 3133111144231423 |
6 | 114524252421253 |
7 | 10243301355420 |
oct | 1370626603341 |
9 | 322510836586 |
10 | 102112102113 |
11 | 3a33a68a73a |
12 | 17959177829 |
13 | 9824276bc8 |
14 | 4d2977b2b7 |
15 | 29c98929e3 |
hex | 17c65b06e1 |
102112102113 has 8 divisors (see below), whose sum is σ = 155599393728. Its totient is φ = 58349772624.
The previous prime is 102112102093. The next prime is 102112102117. The reversal of 102112102113 is 311201211201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 102112102113 - 210 = 102112101089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102112102092 and 102112102101.
It is not an unprimeable number, because it can be changed into a prime (102112102117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2431240506 + ... + 2431240547.
It is an arithmetic number, because the mean of its divisors is an integer number (19449924216).
Almost surely, 2102112102113 is an apocalyptic number.
It is an amenable number.
102112102113 is a deficient number, since it is larger than the sum of its proper divisors (53487291615).
102112102113 is an equidigital number, since it uses as much as digits as its factorization.
102112102113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4862481063.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 102112102113 its reverse (311201211201), we get a palindrome (413313313314).
The spelling of 102112102113 in words is "one hundred two billion, one hundred twelve million, one hundred two thousand, one hundred thirteen".
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