Search a number
-
+
10211219988353 is a prime number
BaseRepresentation
bin1001010010010111110000…
…1000111101111110000001
31100011011221110220101211222
42110211330020331332001
52314300034304111403
633414545242244425
72102510356541516
oct224457410757601
940134843811758
1010211219988353
11328761052856a
12118b004ab6715
13590bb5b37357
142743233c730d
1512a93d40d338
hex9497c23df81

10211219988353 has 2 divisors, whose sum is σ = 10211219988354. Its totient is φ = 10211219988352.

The previous prime is 10211219988323. The next prime is 10211219988367. The reversal of 10211219988353 is 35388991211201.

10211219988353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6645346712449 + 3565873275904 = 2577857^2 + 1888352^2 .

It is a cyclic number.

It is not a de Polignac number, because 10211219988353 - 216 = 10211219922817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10211219988295 and 10211219988304.

It is not a weakly prime, because it can be changed into another prime (10211219988323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105609994176 + 5105609994177.

It is an arithmetic number, because the mean of its divisors is an integer number (5105609994177).

Almost surely, 210211219988353 is an apocalyptic number.

It is an amenable number.

10211219988353 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211219988353 is an equidigital number, since it uses as much as digits as its factorization.

10211219988353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 53.

The spelling of 10211219988353 in words is "ten trillion, two hundred eleven billion, two hundred nineteen million, nine hundred eighty-eight thousand, three hundred fifty-three".