Base | Representation |
---|---|
bin | 1001010010011000000110… |
… | …1000110001110010001101 |
3 | 1100011012011220102220110120 |
4 | 2110212001220301302031 |
5 | 2314300231411310013 |
6 | 33415002335055153 |
7 | 2102512556461443 |
oct | 224460150616215 |
9 | 40135156386416 |
10 | 10211312213133 |
11 | 3287658599399 |
12 | 118b02b9714b9 |
13 | 590bcbc87b25 |
14 | 274331752b93 |
15 | 12a946579123 |
hex | 94981a31c8d |
10211312213133 has 16 divisors (see below), whose sum is σ = 13824865296000. Its totient is φ = 6702964821504.
The previous prime is 10211312213093. The next prime is 10211312213149. The reversal of 10211312213133 is 33131221311201.
It is not a de Polignac number, because 10211312213133 - 229 = 10210775342221 is a prime.
It is a super-2 number, since 2×102113122131332 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10211312213033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39184633 + ... + 39444366.
It is an arithmetic number, because the mean of its divisors is an integer number (864054081000).
Almost surely, 210211312213133 is an apocalyptic number.
It is an amenable number.
10211312213133 is a deficient number, since it is larger than the sum of its proper divisors (3613553082867).
10211312213133 is an equidigital number, since it uses as much as digits as its factorization.
10211312213133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78629668.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 10211312213133 its reverse (33131221311201), we get a palindrome (43342533524334).
The spelling of 10211312213133 in words is "ten trillion, two hundred eleven billion, three hundred twelve million, two hundred thirteen thousand, one hundred thirty-three".
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