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1021132202483 is a prime number
BaseRepresentation
bin11101101110000000011…
…10001110000111110011
310121121201110101112120002
432313000032032013303
5113212234320434413
62101033542540215
7133526415336551
oct16670016160763
93547643345502
101021132202483
11364072564448
12145a9b13766b
13753a53ba773
14375ccc50bd1
151b866ac9958
hexedc038e1f3

1021132202483 has 2 divisors, whose sum is σ = 1021132202484. Its totient is φ = 1021132202482.

The previous prime is 1021132202401. The next prime is 1021132202491. The reversal of 1021132202483 is 3842022311201.

It is a strong prime.

It is an emirp because it is prime and its reverse (3842022311201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1021132202483 - 220 = 1021131153907 is a prime.

It is a super-2 number, since 2×10211322024832 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1021132202183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510566101241 + 510566101242.

It is an arithmetic number, because the mean of its divisors is an integer number (510566101242).

Almost surely, 21021132202483 is an apocalyptic number.

1021132202483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021132202483 is an equidigital number, since it uses as much as digits as its factorization.

1021132202483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1021132202483 its reverse (3842022311201), we get a palindrome (4863154513684).

The spelling of 1021132202483 in words is "one trillion, twenty-one billion, one hundred thirty-two million, two hundred two thousand, four hundred eighty-three".