Base | Representation |
---|---|
bin | 101111100011011011… |
… | …0011010100111000011 |
3 | 100202120221112220001221 |
4 | 1133012312122213003 |
5 | 3133120310320342 |
6 | 114525150335511 |
7 | 10243432042426 |
oct | 1370666324703 |
9 | 322527486057 |
10 | 102120401347 |
11 | 3a344339008 |
12 | 1795baba597 |
13 | 9825bc15b3 |
14 | 4d2a8db9bd |
15 | 29ca481a67 |
hex | 17c6d9a9c3 |
102120401347 has 2 divisors, whose sum is σ = 102120401348. Its totient is φ = 102120401346.
The previous prime is 102120401291. The next prime is 102120401363. The reversal of 102120401347 is 743104021201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102120401347 is a prime.
It is not a weakly prime, because it can be changed into another prime (102120401387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060200673 + 51060200674.
It is an arithmetic number, because the mean of its divisors is an integer number (51060200674).
Almost surely, 2102120401347 is an apocalyptic number.
102120401347 is a deficient number, since it is larger than the sum of its proper divisors (1).
102120401347 is an equidigital number, since it uses as much as digits as its factorization.
102120401347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 102120401347 its reverse (743104021201), we get a palindrome (845224422548).
The spelling of 102120401347 in words is "one hundred two billion, one hundred twenty million, four hundred one thousand, three hundred forty-seven".
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