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10212040462513 is a prime number
BaseRepresentation
bin1001010010011010110100…
…0010110101000010110001
31100011021001122202210210211
42110212231002311002301
52314303224324300023
633415202512024121
72102536611500461
oct224465502650261
940137048683724
1010212040462513
1132879a168298a
12118b1b3832041
13590cb6b08416
142743a0361ba1
1512a98a47ba0d
hex949ad0b50b1

10212040462513 has 2 divisors, whose sum is σ = 10212040462514. Its totient is φ = 10212040462512.

The previous prime is 10212040462489. The next prime is 10212040462567. The reversal of 10212040462513 is 31526404021201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9330379557489 + 881660905024 = 3054567^2 + 938968^2 .

It is a cyclic number.

It is not a de Polignac number, because 10212040462513 - 213 = 10212040454321 is a prime.

It is not a weakly prime, because it can be changed into another prime (10212040460513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106020231256 + 5106020231257.

It is an arithmetic number, because the mean of its divisors is an integer number (5106020231257).

Almost surely, 210212040462513 is an apocalyptic number.

It is an amenable number.

10212040462513 is a deficient number, since it is larger than the sum of its proper divisors (1).

10212040462513 is an equidigital number, since it uses as much as digits as its factorization.

10212040462513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 10212040462513 its reverse (31526404021201), we get a palindrome (41738444483714).

The spelling of 10212040462513 in words is "ten trillion, two hundred twelve billion, forty million, four hundred sixty-two thousand, five hundred thirteen".