Base | Representation |
---|---|
bin | 1001010010011010110100… |
… | …0010110101000010110001 |
3 | 1100011021001122202210210211 |
4 | 2110212231002311002301 |
5 | 2314303224324300023 |
6 | 33415202512024121 |
7 | 2102536611500461 |
oct | 224465502650261 |
9 | 40137048683724 |
10 | 10212040462513 |
11 | 32879a168298a |
12 | 118b1b3832041 |
13 | 590cb6b08416 |
14 | 2743a0361ba1 |
15 | 12a98a47ba0d |
hex | 949ad0b50b1 |
10212040462513 has 2 divisors, whose sum is σ = 10212040462514. Its totient is φ = 10212040462512.
The previous prime is 10212040462489. The next prime is 10212040462567. The reversal of 10212040462513 is 31526404021201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9330379557489 + 881660905024 = 3054567^2 + 938968^2 .
It is a cyclic number.
It is not a de Polignac number, because 10212040462513 - 213 = 10212040454321 is a prime.
It is not a weakly prime, because it can be changed into another prime (10212040460513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106020231256 + 5106020231257.
It is an arithmetic number, because the mean of its divisors is an integer number (5106020231257).
Almost surely, 210212040462513 is an apocalyptic number.
It is an amenable number.
10212040462513 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212040462513 is an equidigital number, since it uses as much as digits as its factorization.
10212040462513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 10212040462513 its reverse (31526404021201), we get a palindrome (41738444483714).
The spelling of 10212040462513 in words is "ten trillion, two hundred twelve billion, forty million, four hundred sixty-two thousand, five hundred thirteen".
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