Base | Representation |
---|---|
bin | 1001010010011011000111… |
… | …0110111001100000001011 |
3 | 1100011021021021201202210202 |
4 | 2110212301312321200023 |
5 | 2314303411013034011 |
6 | 33415214515002415 |
7 | 2102541612103364 |
oct | 224466166714013 |
9 | 40137237652722 |
10 | 10212121221131 |
11 | 3287a33222045 |
12 | 118b21689940b |
13 | 590cca772b9b |
14 | 2743aad84b6b |
15 | 12a9925d023b |
hex | 949b1db980b |
10212121221131 has 2 divisors, whose sum is σ = 10212121221132. Its totient is φ = 10212121221130.
The previous prime is 10212121221101. The next prime is 10212121221143. The reversal of 10212121221131 is 13112212121201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10212121221131 is a prime.
It is a super-2 number, since 2×102121212211312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10212121221101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106060610565 + 5106060610566.
It is an arithmetic number, because the mean of its divisors is an integer number (5106060610566).
Almost surely, 210212121221131 is an apocalyptic number.
10212121221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212121221131 is an equidigital number, since it uses as much as digits as its factorization.
10212121221131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 10212121221131 its reverse (13112212121201), we get a palindrome (23324333342332).
The spelling of 10212121221131 in words is "ten trillion, two hundred twelve billion, one hundred twenty-one million, two hundred twenty-one thousand, one hundred thirty-one".
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