Base | Representation |
---|---|
bin | 101111100011011110… |
… | …1010100111100001011 |
3 | 100202121001221221101001 |
4 | 1133012331110330023 |
5 | 3133121241310011 |
6 | 114525253235431 |
7 | 10243453326541 |
oct | 1370675247413 |
9 | 322531857331 |
10 | 102122213131 |
11 | 3a345366254 |
12 | 17960632b77 |
13 | 98263a7163 |
14 | 4d2ac4dd91 |
15 | 29ca6dd7c1 |
hex | 17c6f54f0b |
102122213131 has 2 divisors, whose sum is σ = 102122213132. Its totient is φ = 102122213130.
The previous prime is 102122213117. The next prime is 102122213147. The reversal of 102122213131 is 131312221201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102122213131 - 213 = 102122204939 is a prime.
It is a super-3 number, since 3×1021222131313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 102122213099 and 102122213108.
It is not a weakly prime, because it can be changed into another prime (102122913131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51061106565 + 51061106566.
It is an arithmetic number, because the mean of its divisors is an integer number (51061106566).
Almost surely, 2102122213131 is an apocalyptic number.
102122213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
102122213131 is an equidigital number, since it uses as much as digits as its factorization.
102122213131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 102122213131 its reverse (131312221201), we get a palindrome (233434434332).
The spelling of 102122213131 in words is "one hundred two billion, one hundred twenty-two million, two hundred thirteen thousand, one hundred thirty-one".
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