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102123100113 = 3283289741521
BaseRepresentation
bin101111100011100000…
…0101101011111010001
3100202121010122000002020
41133013000231133101
53133122003200423
6114525324242053
710243464012516
oct1370700553721
9322533560066
10102123100113
113a3459116a1
12179609a0329
139826627ab8
144d2b00130d
1529ca8164e3
hex17c702d7d1

102123100113 has 16 divisors (see below), whose sum is σ = 136695738816. Its totient is φ = 67816442880.

The previous prime is 102123100097. The next prime is 102123100117. The reversal of 102123100113 is 311001321201.

It is a happy number.

It is not a de Polignac number, because 102123100113 - 24 = 102123100097 is a prime.

It is a super-2 number, since 2×1021231001132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102123100092 and 102123100101.

It is not an unprimeable number, because it can be changed into a prime (102123100117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2438793 + ... + 2480313.

It is an arithmetic number, because the mean of its divisors is an integer number (8543483676).

Almost surely, 2102123100113 is an apocalyptic number.

It is an amenable number.

102123100113 is a deficient number, since it is larger than the sum of its proper divisors (34572638703).

102123100113 is a wasteful number, since it uses less digits than its factorization.

102123100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44704.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 102123100113 its reverse (311001321201), we get a palindrome (413124421314).

The spelling of 102123100113 in words is "one hundred two billion, one hundred twenty-three million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 283 849 2897 8691 41521 124563 819851 2459553 11750443 35251329 120286337 360859011 34041033371 102123100113