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10212313131411 = 33404104377137
BaseRepresentation
bin1001010010011011110101…
…0010111110100110010011
31100011021202122211211012220
42110212331102332212103
52314304304130201121
633415245532152123
72102546432235516
oct224467522764623
940137678754186
1010212313131411
11328802158a086
12118b26b008643
1359102b456c71
142743c865cd7d
1512a9a438c6c6
hex949bd4be993

10212313131411 has 4 divisors (see below), whose sum is σ = 13616417508552. Its totient is φ = 6808208754272.

The previous prime is 10212313131389. The next prime is 10212313131451. The reversal of 10212313131411 is 11413131321201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10212313131411 - 217 = 10212313000339 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10212313131451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1702052188566 + ... + 1702052188571.

It is an arithmetic number, because the mean of its divisors is an integer number (3404104377138).

Almost surely, 210212313131411 is an apocalyptic number.

10212313131411 is a deficient number, since it is larger than the sum of its proper divisors (3404104377141).

10212313131411 is an equidigital number, since it uses as much as digits as its factorization.

10212313131411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3404104377140.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 10212313131411 its reverse (11413131321201), we get a palindrome (21625444452612).

The spelling of 10212313131411 in words is "ten trillion, two hundred twelve billion, three hundred thirteen million, one hundred thirty-one thousand, four hundred eleven".

Divisors: 1 3 3404104377137 10212313131411