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102124213314113 is a prime number
BaseRepresentation
bin10111001110000110100101…
…011101010010001001000001
3111101120222110000102112011002
4113032012211131102021001
5101341200342102022423
61001111114350101345
730340142131325324
oct2716064535221101
9441528400375132
10102124213314113
112a5a36aa052361
12b5544344aa855
1344ca36c752543
141b30ba44087bb
15bc17425b2228
hex5ce1a5752241

102124213314113 has 2 divisors, whose sum is σ = 102124213314114. Its totient is φ = 102124213314112.

The previous prime is 102124213314091. The next prime is 102124213314161. The reversal of 102124213314113 is 311413312421201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90639387102784 + 11484826211329 = 9520472^2 + 3388927^2 .

It is a cyclic number.

It is not a de Polignac number, because 102124213314113 - 222 = 102124209119809 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (102124213314313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51062106657056 + 51062106657057.

It is an arithmetic number, because the mean of its divisors is an integer number (51062106657057).

Almost surely, 2102124213314113 is an apocalyptic number.

It is an amenable number.

102124213314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102124213314113 is an equidigital number, since it uses as much as digits as its factorization.

102124213314113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 102124213314113 its reverse (311413312421201), we get a palindrome (413537525735314).

The spelling of 102124213314113 in words is "one hundred two trillion, one hundred twenty-four billion, two hundred thirteen million, three hundred fourteen thousand, one hundred thirteen".