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10213102231307 is a prime number
BaseRepresentation
bin1001010010011110110001…
…0101001001111100001011
31100011100210122200020202222
42110213230111021330023
52314312413132400212
633415500121244255
72102605123413353
oct224475425117413
940140718606688
1010213102231307
113288396a55558
12118b44b33368b
13591125a91691
1427446138bb63
1512a9ed7aec72
hex949ec549f0b

10213102231307 has 2 divisors, whose sum is σ = 10213102231308. Its totient is φ = 10213102231306.

The previous prime is 10213102231301. The next prime is 10213102231327. The reversal of 10213102231307 is 70313220131201.

10213102231307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10213102231307 - 232 = 10208807264011 is a prime.

It is not a weakly prime, because it can be changed into another prime (10213102231301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106551115653 + 5106551115654.

It is an arithmetic number, because the mean of its divisors is an integer number (5106551115654).

Almost surely, 210213102231307 is an apocalyptic number.

10213102231307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213102231307 is an equidigital number, since it uses as much as digits as its factorization.

10213102231307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 10213102231307 its reverse (70313220131201), we get a palindrome (80526322362508).

The spelling of 10213102231307 in words is "ten trillion, two hundred thirteen billion, one hundred two million, two hundred thirty-one thousand, three hundred seven".