10213102414433 has 2 divisors, whose sum is σ = 10213102414434. Its totient is φ = 10213102414432.

The previous prime is 10213102414429. The next prime is 10213102414447. The reversal of 10213102414433 is 33441420131201.

10213102414433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9328943966224 + 884158448209 = 3054332^2 + 940297^2 .

It is a cyclic number.

It is not a de Polignac number, because 10213102414433 - 2² = 10213102414429 is a prime.

It is a super-2 number, since 2×10213102414433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10213102414396 and 10213102414405.

It is not a weakly prime, because it can be changed into another prime (10213102414423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106551207216 + 5106551207217.

It is an arithmetic number, because the mean of its divisors is an integer number (5106551207217).

Almost surely, 2^{10213102414433} is an apocalyptic number.

It is an amenable number.

10213102414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213102414433 is an equidigital number, since it uses as much as digits as its factorization.

10213102414433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 10213102414433 its reverse (33441420131201), we get a palindrome (43654522545634).

The spelling of 10213102414433 in words is "ten trillion, two hundred thirteen billion, one hundred two million, four hundred fourteen thousand, four hundred thirty-three".