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10213104124123 = 19951322131277
BaseRepresentation
bin1001010010011110110001…
…1100011000000011011011
31100011100210210020102020021
42110213230130120003123
52314312414123432443
633415500230011311
72102605145455645
oct224475434300333
940140723212207
1010213104124123
11328839802866a
12118b44baa6b37
135911262a50a4
14274461721895
1512a9eda359ed
hex949ec7180db

10213104124123 has 4 divisors (see below), whose sum is σ = 10264426255600. Its totient is φ = 10161781992648.

The previous prime is 10213104124087. The next prime is 10213104124241. The reversal of 10213104124123 is 32142140131201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10213104124123 - 217 = 10213103993051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10213104124823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25661065440 + ... + 25661065837.

It is an arithmetic number, because the mean of its divisors is an integer number (2566106563900).

Almost surely, 210213104124123 is an apocalyptic number.

10213104124123 is a deficient number, since it is larger than the sum of its proper divisors (51322131477).

10213104124123 is an equidigital number, since it uses as much as digits as its factorization.

10213104124123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51322131476.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10213104124123 its reverse (32142140131201), we get a palindrome (42355244255324).

The spelling of 10213104124123 in words is "ten trillion, two hundred thirteen billion, one hundred four million, one hundred twenty-four thousand, one hundred twenty-three".

Divisors: 1 199 51322131277 10213104124123