Search a number
-
+
10213113555 = 33575652693
BaseRepresentation
bin10011000001011111…
…11011111011010011
3222100202202220222000
421200233323323103
5131404024113210
64405234245043
7511043014161
oct114057737323
928322686860
1010213113555
114371044417
121b90426783
13c69bb6578
146cc59a231
153eb957ac0
hex260bfbed3

10213113555 has 16 divisors (see below), whose sum is σ = 18156646560. Its totient is φ = 5446993824.

The previous prime is 10213113553. The next prime is 10213113671. The reversal of 10213113555 is 55531131201.

10213113555 is a `hidden beast` number, since 102 + 1 + 3 + 1 + 1 + 3 + 555 = 666.

It is not a de Polignac number, because 10213113555 - 21 = 10213113553 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (10213113553) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37826212 + ... + 37826481.

It is an arithmetic number, because the mean of its divisors is an integer number (1134790410).

Almost surely, 210213113555 is an apocalyptic number.

10213113555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10213113555 is a deficient number, since it is larger than the sum of its proper divisors (7943533005).

10213113555 is an equidigital number, since it uses as much as digits as its factorization.

10213113555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75652707 (or 75652701 counting only the distinct ones).

The product of its (nonzero) digits is 2250, while the sum is 27.

Adding to 10213113555 its reverse (55531131201), we get a palindrome (65744244756).

The spelling of 10213113555 in words is "ten billion, two hundred thirteen million, one hundred thirteen thousand, five hundred fifty-five".

Divisors: 1 3 5 9 15 27 45 135 75652693 226958079 378263465 680874237 1134790395 2042622711 3404371185 10213113555