Base | Representation |
---|---|
bin | 1001010010011111001101… |
… | …0110110101001111011011 |
3 | 1100011101002212111011202111 |
4 | 2110213303112311033123 |
5 | 2314313133322030243 |
6 | 33415515532013151 |
7 | 2102611054365025 |
oct | 224476326651733 |
9 | 40141085434674 |
10 | 10213220111323 |
11 | 3288447549559 |
12 | 118b4829011b7 |
13 | 591144325678 |
14 | 274472cb5015 |
15 | 12aa08ce739d |
hex | 949f35b53db |
10213220111323 has 2 divisors, whose sum is σ = 10213220111324. Its totient is φ = 10213220111322.
The previous prime is 10213220111309. The next prime is 10213220111363. The reversal of 10213220111323 is 32311102231201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10213220111323 - 229 = 10212683240411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10213220111294 and 10213220111303.
It is not a weakly prime, because it can be changed into another prime (10213220111363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106610055661 + 5106610055662.
It is an arithmetic number, because the mean of its divisors is an integer number (5106610055662).
Almost surely, 210213220111323 is an apocalyptic number.
10213220111323 is a deficient number, since it is larger than the sum of its proper divisors (1).
10213220111323 is an equidigital number, since it uses as much as digits as its factorization.
10213220111323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10213220111323 its reverse (32311102231201), we get a palindrome (42524322342524).
The spelling of 10213220111323 in words is "ten trillion, two hundred thirteen billion, two hundred twenty million, one hundred eleven thousand, three hundred twenty-three".
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