Base | Representation |
---|---|
bin | 11101101110010111010… |
… | …10000001011110010011 |
3 | 10121122012211100220021101 |
4 | 32313023222001132103 |
5 | 113213132423240313 |
6 | 2101104554405231 |
7 | 133534235050054 |
oct | 16671352013623 |
9 | 3548184326241 |
10 | 1021324040083 |
11 | 364160881916 |
12 | 145b33430817 |
13 | 75406077739 |
14 | 3760a50a72b |
15 | 1b8788705dd |
hex | edcba81793 |
1021324040083 has 2 divisors, whose sum is σ = 1021324040084. Its totient is φ = 1021324040082.
The previous prime is 1021324040027. The next prime is 1021324040129. The reversal of 1021324040083 is 3800404231201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1021324040083 is a prime.
It is a super-2 number, since 2×10213240400832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1021324040003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510662020041 + 510662020042.
It is an arithmetic number, because the mean of its divisors is an integer number (510662020042).
Almost surely, 21021324040083 is an apocalyptic number.
1021324040083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021324040083 is an equidigital number, since it uses as much as digits as its factorization.
1021324040083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1021324040083 its reverse (3800404231201), we get a palindrome (4821728271284).
The spelling of 1021324040083 in words is "one trillion, twenty-one billion, three hundred twenty-four million, forty thousand, eighty-three".
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