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102134343332 = 22729125781211
BaseRepresentation
bin101111100011110101…
…1100110011010100100
3100202121220210012212202
41133013223212122210
53133132342441312
6114530405234032
710243661410550
oct1370753463244
9322556705782
10102134343332
113a3511a090a
1217964702918
139828a634a8
144d2c6ca860
1529cb7d79c2
hex17c7ae66a4

102134343332 has 24 divisors (see below), whose sum is σ = 211312436160. Its totient is φ = 42262486560.

The previous prime is 102134343323. The next prime is 102134343349. The reversal of 102134343332 is 233343431201.

It is a Harshad number since it is a multiple of its sum of digits (29).

It is a junction number, because it is equal to n+sod(n) for n = 102134343295 and 102134343304.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62889794 + ... + 62891417.

It is an arithmetic number, because the mean of its divisors is an integer number (8804684840).

Almost surely, 2102134343332 is an apocalyptic number.

It is an amenable number.

102134343332 is an abundant number, since it is smaller than the sum of its proper divisors (109178092828).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102134343332 is a wasteful number, since it uses less digits than its factorization.

102134343332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125781251 (or 125781249 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 102134343332 its reverse (233343431201), we get a palindrome (335477774533).

The spelling of 102134343332 in words is "one hundred two billion, one hundred thirty-four million, three hundred forty-three thousand, three hundred thirty-two".

Divisors: 1 2 4 7 14 28 29 58 116 203 406 812 125781211 251562422 503124844 880468477 1760936954 3521873908 3647655119 7295310238 14590620476 25533585833 51067171666 102134343332