Base | Representation |
---|---|
bin | 10111001110010000110000… |
… | …011001001111011101001001 |
3 | 111101122000122010001010121122 |
4 | 113032100300121033131021 |
5 | 101341340223330102103 |
6 | 1001120122151045025 |
7 | 30341006560446344 |
oct | 2716206031173511 |
9 | 441560563033548 |
10 | 102135134222153 |
11 | 2a5a82a367a19a |
12 | b556581970775 |
13 | 44cb3c0176bc6 |
14 | 1b3151c9ab45b |
15 | bc1b8122bb38 |
hex | 5ce43064f749 |
102135134222153 has 32 divisors (see below), whose sum is σ = 105600607200000. Its totient is φ = 98740901788672.
The previous prime is 102135134222119. The next prime is 102135134222161. The reversal of 102135134222153 is 351222431531201.
It is a cyclic number.
It is not a de Polignac number, because 102135134222153 - 26 = 102135134222089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (102135134222353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 846038525 + ... + 846159237.
It is an arithmetic number, because the mean of its divisors is an integer number (3300018975000).
Almost surely, 2102135134222153 is an apocalyptic number.
It is an amenable number.
102135134222153 is a deficient number, since it is larger than the sum of its proper divisors (3465472977847).
102135134222153 is a wasteful number, since it uses less digits than its factorization.
102135134222153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121729.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 102135134222153 its reverse (351222431531201), we get a palindrome (453357565753354).
The spelling of 102135134222153 in words is "one hundred two trillion, one hundred thirty-five billion, one hundred thirty-four million, two hundred twenty-two thousand, one hundred fifty-three".
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