Base | Representation |
---|---|
bin | 11101101110101010011… |
… | …01001001000011101011 |
3 | 10121122121222210221210112 |
4 | 32313111031021003223 |
5 | 113213444431204011 |
6 | 2101132520204535 |
7 | 133541221534364 |
oct | 16672515110353 |
9 | 3548558727715 |
10 | 1021484241131 |
11 | 364233251282 |
12 | 145b7900974b |
13 | 75430308863 |
14 | 376238ccb6b |
15 | 1b88796758b |
hex | edd53490eb |
1021484241131 has 2 divisors, whose sum is σ = 1021484241132. Its totient is φ = 1021484241130.
The previous prime is 1021484241119. The next prime is 1021484241191. The reversal of 1021484241131 is 1311424841201.
It is a weak prime.
It is an emirp because it is prime and its reverse (1311424841201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1021484241131 - 210 = 1021484240107 is a prime.
It is a super-2 number, since 2×10214842411312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1021484241191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510742120565 + 510742120566.
It is an arithmetic number, because the mean of its divisors is an integer number (510742120566).
Almost surely, 21021484241131 is an apocalyptic number.
1021484241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021484241131 is an equidigital number, since it uses as much as digits as its factorization.
1021484241131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 32.
The spelling of 1021484241131 in words is "one trillion, twenty-one billion, four hundred eighty-four million, two hundred forty-one thousand, one hundred thirty-one".
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