Base | Representation |
---|---|
bin | 101111100100011001… |
… | …0110001100010111011 |
3 | 100202200012220010120221 |
4 | 1133020302301202323 |
5 | 3133202132014042 |
6 | 114532313200511 |
7 | 10244306116531 |
oct | 1371062614273 |
9 | 322605803527 |
10 | 102153001147 |
11 | 3a36078479a |
12 | 1796aa00137 |
13 | 982c896a12 |
14 | 4d30d86151 |
15 | 29cd270d67 |
hex | 17c8cb18bb |
102153001147 has 2 divisors, whose sum is σ = 102153001148. Its totient is φ = 102153001146.
The previous prime is 102153001121. The next prime is 102153001157. The reversal of 102153001147 is 741100351201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102153001147 - 223 = 102144612539 is a prime.
It is not a weakly prime, because it can be changed into another prime (102153001157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51076500573 + 51076500574.
It is an arithmetic number, because the mean of its divisors is an integer number (51076500574).
Almost surely, 2102153001147 is an apocalyptic number.
102153001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
102153001147 is an equidigital number, since it uses as much as digits as its factorization.
102153001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 102153001147 its reverse (741100351201), we get a palindrome (843253352348).
The spelling of 102153001147 in words is "one hundred two billion, one hundred fifty-three million, one thousand, one hundred forty-seven".
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