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10222212101113 is a prime number
BaseRepresentation
bin1001010011000000101101…
…0100100011001111111001
31100012020022112111120211101
42110300023110203033321
52314440042244213423
633424004105331401
72103346642134505
oct224601324431771
940166275446741
1010222212101113
113291241269581
121191172196b61
13591c4822c99c
14274a87203305
1512ad834407ad
hex94c0b5233f9

10222212101113 has 2 divisors, whose sum is σ = 10222212101114. Its totient is φ = 10222212101112.

The previous prime is 10222212101081. The next prime is 10222212101149. The reversal of 10222212101113 is 31110121222201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5922175336704 + 4300036764409 = 2433552^2 + 2073653^2 .

It is a cyclic number.

It is not a de Polignac number, because 10222212101113 - 25 = 10222212101081 is a prime.

It is not a weakly prime, because it can be changed into another prime (10228212101113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111106050556 + 5111106050557.

It is an arithmetic number, because the mean of its divisors is an integer number (5111106050557).

Almost surely, 210222212101113 is an apocalyptic number.

It is an amenable number.

10222212101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10222212101113 is an equidigital number, since it uses as much as digits as its factorization.

10222212101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 10222212101113 its reverse (31110121222201), we get a palindrome (41332333323314).

The spelling of 10222212101113 in words is "ten trillion, two hundred twenty-two billion, two hundred twelve million, one hundred one thousand, one hundred thirteen".