Base | Representation |
---|---|
bin | 1001010011000000101101… |
… | …0100100011001111111001 |
3 | 1100012020022112111120211101 |
4 | 2110300023110203033321 |
5 | 2314440042244213423 |
6 | 33424004105331401 |
7 | 2103346642134505 |
oct | 224601324431771 |
9 | 40166275446741 |
10 | 10222212101113 |
11 | 3291241269581 |
12 | 1191172196b61 |
13 | 591c4822c99c |
14 | 274a87203305 |
15 | 12ad834407ad |
hex | 94c0b5233f9 |
10222212101113 has 2 divisors, whose sum is σ = 10222212101114. Its totient is φ = 10222212101112.
The previous prime is 10222212101081. The next prime is 10222212101149. The reversal of 10222212101113 is 31110121222201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5922175336704 + 4300036764409 = 2433552^2 + 2073653^2 .
It is a cyclic number.
It is not a de Polignac number, because 10222212101113 - 25 = 10222212101081 is a prime.
It is not a weakly prime, because it can be changed into another prime (10228212101113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111106050556 + 5111106050557.
It is an arithmetic number, because the mean of its divisors is an integer number (5111106050557).
Almost surely, 210222212101113 is an apocalyptic number.
It is an amenable number.
10222212101113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10222212101113 is an equidigital number, since it uses as much as digits as its factorization.
10222212101113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 10222212101113 its reverse (31110121222201), we get a palindrome (41332333323314).
The spelling of 10222212101113 in words is "ten trillion, two hundred twenty-two billion, two hundred twelve million, one hundred one thousand, one hundred thirteen".
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