Base | Representation |
---|---|
bin | 11101110000001101011… |
… | …00001000110011101001 |
3 | 10121201202211222221110211 |
4 | 32320012230020303221 |
5 | 113222144444401103 |
6 | 2101351134341121 |
7 | 133600622310013 |
oct | 16700654106351 |
9 | 3551684887424 |
10 | 1022314450153 |
11 | 364619945637 |
12 | 14616b05a7a1 |
13 | 755333078b9 |
14 | 376a1c7d1b3 |
15 | 1b8d57aa36d |
hex | ee06b08ce9 |
1022314450153 has 2 divisors, whose sum is σ = 1022314450154. Its totient is φ = 1022314450152.
The previous prime is 1022314450081. The next prime is 1022314450169. The reversal of 1022314450153 is 3510544132201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 991623614809 + 30690835344 = 995803^2 + 175188^2 .
It is a cyclic number.
It is not a de Polignac number, because 1022314450153 - 29 = 1022314449641 is a prime.
It is not a weakly prime, because it can be changed into another prime (1022314450253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511157225076 + 511157225077.
It is an arithmetic number, because the mean of its divisors is an integer number (511157225077).
Almost surely, 21022314450153 is an apocalyptic number.
It is an amenable number.
1022314450153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1022314450153 is an equidigital number, since it uses as much as digits as its factorization.
1022314450153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1022314450153 its reverse (3510544132201), we get a palindrome (4532858582354).
The spelling of 1022314450153 in words is "one trillion, twenty-two billion, three hundred fourteen million, four hundred fifty thousand, one hundred fifty-three".
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