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1022425653131 = 5771771968203
BaseRepresentation
bin11101110000011010101…
…00010101111110001011
310121202001121020122021122
432320031110111332023
5113222411431400011
62101410150025455
7133603442441651
oct16701524257613
93552047218248
101022425653131
11364676699023
121461a034828b
137555037168c
14376b2948dd1
151b8e04243db
hexee0d515f8b

1022425653131 has 4 divisors (see below), whose sum is σ = 1024197621912. Its totient is φ = 1020653684352.

The previous prime is 1022425653089. The next prime is 1022425653133. The reversal of 1022425653131 is 1313565242201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1022425653131 is a prime.

It is a super-2 number, since 2×10224256531312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1022425653091 and 1022425653100.

It is not an unprimeable number, because it can be changed into a prime (1022425653133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885983525 + ... + 885984678.

It is an arithmetic number, because the mean of its divisors is an integer number (256049405478).

Almost surely, 21022425653131 is an apocalyptic number.

1022425653131 is a deficient number, since it is larger than the sum of its proper divisors (1771968781).

1022425653131 is an equidigital number, since it uses as much as digits as its factorization.

1022425653131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1771968780.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 1022425653131 in words is "one trillion, twenty-two billion, four hundred twenty-five million, six hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 577 1771968203 1022425653131