10230011313 has 4 divisors (see below), whose sum is σ = 13640015088. Its totient is φ = 6820007540.

The previous prime is 10230011299. The next prime is 10230011327. The reversal of 10230011313 is 31311003201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10230011299) and next prime (10230011327).

It is a cyclic number.

It is not a de Polignac number, because 10230011313 - 2⁹ = 10230010801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10230011292 and 10230011301.

It is not an unprimeable number, because it can be changed into a prime (10230011333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1705001883 + ... + 1705001888.

It is an arithmetic number, because the mean of its divisors is an integer number (3410003772).

Almost surely, 2^10230011313 is an apocalyptic number.

It is an amenable number.

10230011313 is a deficient number, since it is larger than the sum of its proper divisors (3410003775).

10230011313 is an equidigital number, since it uses as much as digits as its factorization.

10230011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3410003774.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10230011313 its reverse (31311003201), we get a palindrome (41541014514).

The spelling of 10230011313 in words is "ten billion, two hundred thirty million, eleven thousand, three hundred thirteen".