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10230111313 = 10639961567
BaseRepresentation
bin10011000011100001…
…10001110001010001
3222101221202111111121
421201300301301101
5131422402030223
64411042442241
7511340340262
oct114160616121
928357674447
1010230111313
11437a6a4054
121b96063381
13c70588306
146d0942969
153ed1b415d
hex261c31c51

10230111313 has 4 divisors (see below), whose sum is σ = 10231083520. Its totient is φ = 10229139108.

The previous prime is 10230111289. The next prime is 10230111329. The reversal of 10230111313 is 31311103201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31311103201 = 74473014743.

It is a cyclic number.

It is not a de Polignac number, because 10230111313 - 221 = 10228014161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10230111013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470145 + ... + 491422.

It is an arithmetic number, because the mean of its divisors is an integer number (2557770880).

Almost surely, 210230111313 is an apocalyptic number.

It is an amenable number.

10230111313 is a deficient number, since it is larger than the sum of its proper divisors (972207).

10230111313 is an equidigital number, since it uses as much as digits as its factorization.

10230111313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 972206.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10230111313 its reverse (31311103201), we get a palindrome (41541214514).

The spelling of 10230111313 in words is "ten billion, two hundred thirty million, one hundred eleven thousand, three hundred thirteen".

Divisors: 1 10639 961567 10230111313