102311313000001 has 4 divisors (see below), whose sum is σ = 116927214857152. Its totient is φ = 87695411142852.

The previous prime is 102311312999969. The next prime is 102311313000031. The reversal of 102311313000001 is 100000313113201.

102311313000001 is digitally balanced in base 8, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102311313000001 - 2⁵ = 102311312999969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (102311313000031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7307950928565 + ... + 7307950928578.

It is an arithmetic number, because the mean of its divisors is an integer number (29231803714288).

Almost surely, 2^{102311313000001} is an apocalyptic number.

It is an amenable number.

102311313000001 is a deficient number, since it is larger than the sum of its proper divisors (14615901857151).

102311313000001 is an equidigital number, since it uses as much as digits as its factorization.

102311313000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14615901857150.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 102311313000001 its reverse (100000313113201), we get a palindrome (202311626113202).

The spelling of 102311313000001 in words is "one hundred two trillion, three hundred eleven billion, three hundred thirteen million, one", and thus it is an aban number.