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1023123332131 is a prime number
BaseRepresentation
bin11101110001101101110…
…01110001110000100011
310121210212020001101221121
432320312321301300203
5113230324033112011
62102003311433111
7133626643555345
oct16706671616043
93553766041847
101023123332131
113649a44a263a
12146355b25797
1375631a7a4a4
143773b47b295
151b9317d8e71
hexee36e71c23

1023123332131 has 2 divisors, whose sum is σ = 1023123332132. Its totient is φ = 1023123332130.

The previous prime is 1023123332093. The next prime is 1023123332159. The reversal of 1023123332131 is 1312333213201.

It is a strong prime.

It is an emirp because it is prime and its reverse (1312333213201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1023123332131 - 237 = 885684378659 is a prime.

It is a super-2 number, since 2×10231233321312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1023123332096 and 1023123332105.

It is not a weakly prime, because it can be changed into another prime (1023123339131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511561666065 + 511561666066.

It is an arithmetic number, because the mean of its divisors is an integer number (511561666066).

Almost surely, 21023123332131 is an apocalyptic number.

1023123332131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1023123332131 is an equidigital number, since it uses as much as digits as its factorization.

1023123332131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1023123332131 its reverse (1312333213201), we get a palindrome (2335456545332).

The spelling of 1023123332131 in words is "one trillion, twenty-three billion, one hundred twenty-three million, three hundred thirty-two thousand, one hundred thirty-one".