Base | Representation |
---|---|
bin | 10011000011111001… |
… | …11111011101101011 |
3 | 222102011210011120110 |
4 | 21201330333131223 |
5 | 131424212010011 |
6 | 4411235225403 |
7 | 511406504106 |
oct | 114174773553 |
9 | 28364704513 |
10 | 10233313131 |
11 | 4381490688 |
12 | 1b97148263 |
13 | c71139792 |
14 | 6d113773d |
15 | 3ed5e7ba6 |
hex | 261f3f76b |
10233313131 has 4 divisors (see below), whose sum is σ = 13644417512. Its totient is φ = 6822208752.
The previous prime is 10233313121. The next prime is 10233313159. The reversal of 10233313131 is 13131333201.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10233313131 - 25 = 10233313099 is a prime.
It is a super-2 number, since 2×102333131312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10233313098 and 10233313107.
It is not an unprimeable number, because it can be changed into a prime (10233313121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1705552186 + ... + 1705552191.
It is an arithmetic number, because the mean of its divisors is an integer number (3411104378).
Almost surely, 210233313131 is an apocalyptic number.
10233313131 is a deficient number, since it is larger than the sum of its proper divisors (3411104381).
10233313131 is an equidigital number, since it uses as much as digits as its factorization.
10233313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3411104380.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 10233313131 its reverse (13131333201), we get a palindrome (23364646332).
The spelling of 10233313131 in words is "ten billion, two hundred thirty-three million, three hundred thirteen thousand, one hundred thirty-one".
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