102340433131 has 2 divisors, whose sum is σ = 102340433132. Its totient is φ = 102340433130.

The previous prime is 102340433113. The next prime is 102340433147. The reversal of 102340433131 is 131334043201.

Together with previous prime (102340433113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102340433131 - 2²⁷ = 102206215403 is a prime.

It is a super-2 number, since 2×102340433131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102340433096 and 102340433105.

It is not a weakly prime, because it can be changed into another prime (102340430131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51170216565 + 51170216566.

It is an arithmetic number, because the mean of its divisors is an integer number (51170216566).

Almost surely, 2^102340433131 is an apocalyptic number.

102340433131 is a deficient number, since it is larger than the sum of its proper divisors (1).

102340433131 is an equidigital number, since it uses as much as digits as its factorization.

102340433131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 102340433131 its reverse (131334043201), we get a palindrome (233674476332).

The spelling of 102340433131 in words is "one hundred two billion, three hundred forty million, four hundred thirty-three thousand, one hundred thirty-one".