Base | Representation |
---|---|
bin | 1001010011101101101111… |
… | …1100010101010101111001 |
3 | 1100020101112010000110022220 |
4 | 2110323123330111111321 |
5 | 2320134322321003213 |
6 | 33433323512434253 |
7 | 2104255355505021 |
oct | 224733374252571 |
9 | 40211463013286 |
10 | 10234302125433 |
11 | 3296385818811 |
12 | 11935870a8989 |
13 | 593123c24529 |
14 | 2754b2b76a81 |
15 | 12b33ea44e23 |
hex | 94edbf15579 |
10234302125433 has 32 divisors (see below), whose sum is σ = 13734550781952. Its totient is φ = 6778643284800.
The previous prime is 10234302125423. The next prime is 10234302125441. The reversal of 10234302125433 is 33452120343201.
It is not a de Polignac number, because 10234302125433 - 25 = 10234302125401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10234302125394 and 10234302125403.
It is not an unprimeable number, because it can be changed into a prime (10234302125413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 349147848 + ... + 349177158.
It is an arithmetic number, because the mean of its divisors is an integer number (429204711936).
Almost surely, 210234302125433 is an apocalyptic number.
It is an amenable number.
10234302125433 is a deficient number, since it is larger than the sum of its proper divisors (3500248656519).
10234302125433 is a wasteful number, since it uses less digits than its factorization.
10234302125433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30845.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 10234302125433 its reverse (33452120343201), we get a palindrome (43686422468634).
The spelling of 10234302125433 in words is "ten trillion, two hundred thirty-four billion, three hundred two million, one hundred twenty-five thousand, four hundred thirty-three".
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