Base | Representation |
---|---|
bin | 1001010011101110010011… |
… | …1101100000111111101011 |
3 | 1100020101220122201112112001 |
4 | 2110323210331200333223 |
5 | 2320140130034232001 |
6 | 33433350515431431 |
7 | 2104262203540651 |
oct | 224734475407753 |
9 | 40211818645461 |
10 | 10234453430251 |
11 | 3296453171316 |
12 | 11936098b5577 |
13 | 59314938c2cb |
14 | 2754c8cc0dd1 |
15 | 12b34ce81001 |
hex | 94ee4f60feb |
10234453430251 has 2 divisors, whose sum is σ = 10234453430252. Its totient is φ = 10234453430250.
The previous prime is 10234453430237. The next prime is 10234453430303. The reversal of 10234453430251 is 15203435443201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10234453430251 - 235 = 10200093691883 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10234453430251.
It is not a weakly prime, because it can be changed into another prime (10234453460251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5117226715125 + 5117226715126.
It is an arithmetic number, because the mean of its divisors is an integer number (5117226715126).
Almost surely, 210234453430251 is an apocalyptic number.
10234453430251 is a deficient number, since it is larger than the sum of its proper divisors (1).
10234453430251 is an equidigital number, since it uses as much as digits as its factorization.
10234453430251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 10234453430251 its reverse (15203435443201), we get a palindrome (25437888873452).
The spelling of 10234453430251 in words is "ten trillion, two hundred thirty-four billion, four hundred fifty-three million, four hundred thirty thousand, two hundred fifty-one".
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