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1024113002131 is a prime number
BaseRepresentation
bin11101110011100011110…
…01000100011010010011
310121220102012021211222001
432321301321010122103
5113234340412032011
62102245423454431
7133663321613542
oct16716171043223
93556365254861
101024113002131
1136536210032a
12146591457417
137575bb0b83b
14377d2a9a159
151b98d6297c1
hexee71e44693

1024113002131 has 2 divisors, whose sum is σ = 1024113002132. Its totient is φ = 1024113002130.

The previous prime is 1024113002123. The next prime is 1024113002197. The reversal of 1024113002131 is 1312003114201.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1024113002131 - 23 = 1024113002123 is a prime.

It is a super-2 number, since 2×10241130021312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1024113002099 and 1024113002108.

It is not a weakly prime, because it can be changed into another prime (1024113002531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 512056501065 + 512056501066.

It is an arithmetic number, because the mean of its divisors is an integer number (512056501066).

Almost surely, 21024113002131 is an apocalyptic number.

1024113002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1024113002131 is an equidigital number, since it uses as much as digits as its factorization.

1024113002131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1024113002131 its reverse (1312003114201), we get a palindrome (2336116116332).

The spelling of 1024113002131 in words is "one trillion, twenty-four billion, one hundred thirteen million, two thousand, one hundred thirty-one".