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102413433 = 334137811
BaseRepresentation
bin1100001101010…
…11010001111001
321010201010211010
412012223101321
5202204212213
614055024133
72352333303
oct606532171
9233633733
10102413433
115289a801
122a36b049
13182aa185
14d85c973
158eceac3
hex61ab479

102413433 has 4 divisors (see below), whose sum is σ = 136551248. Its totient is φ = 68275620.

The previous prime is 102413387. The next prime is 102413459. The reversal of 102413433 is 334314201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 102413433 - 28 = 102413177 is a prime.

It is a super-3 number, since 3×1024134333 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102413483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17068903 + ... + 17068908.

It is an arithmetic number, because the mean of its divisors is an integer number (34137812).

Almost surely, 2102413433 is an apocalyptic number.

It is an amenable number.

102413433 is a deficient number, since it is larger than the sum of its proper divisors (34137815).

102413433 is an equidigital number, since it uses as much as digits as its factorization.

102413433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34137814.

The product of its (nonzero) digits is 864, while the sum is 21.

The square root of 102413433 is about 10119.9522232074. The cubic root of 102413433 is about 467.8632946833.

Adding to 102413433 its reverse (334314201), we get a palindrome (436727634).

The spelling of 102413433 in words is "one hundred two million, four hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 3 34137811 102413433