Base | Representation |
---|---|
bin | 10111010010100101011101… |
… | …100010010101101010111011 |
3 | 111102200102112020010011210202 |
4 | 113102211131202111222323 |
5 | 101411222214021400201 |
6 | 1001504420131432415 |
7 | 30401325334610024 |
oct | 2722453542255273 |
9 | 442612466104722 |
10 | 102432244325051 |
11 | 2a7022a8577a83 |
12 | b5a407b45570b |
13 | 452041c361414 |
14 | 1b41a65da7c4b |
15 | bc976ed44c6b |
hex | 5d295d895abb |
102432244325051 has 2 divisors, whose sum is σ = 102432244325052. Its totient is φ = 102432244325050.
The previous prime is 102432244325027. The next prime is 102432244325119. The reversal of 102432244325051 is 150523442234201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102432244325051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102432244324996 and 102432244325014.
It is not a weakly prime, because it can be changed into another prime (102432244325251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51216122162525 + 51216122162526.
It is an arithmetic number, because the mean of its divisors is an integer number (51216122162526).
Almost surely, 2102432244325051 is an apocalyptic number.
102432244325051 is a deficient number, since it is larger than the sum of its proper divisors (1).
102432244325051 is an equidigital number, since it uses as much as digits as its factorization.
102432244325051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 102432244325051 its reverse (150523442234201), we get a palindrome (252955686559252).
The spelling of 102432244325051 in words is "one hundred two trillion, four hundred thirty-two billion, two hundred forty-four million, three hundred twenty-five thousand, fifty-one".
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